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a^2-2ab+b^2 We multiply each term as follows a(a)+(a)(-b)+(-b)(a)+(-b)(-b) a^2-ab-ba+b^2 a^2-ab-ab+b^2 a^2-2ab+b^2 Or you can use the FOIL method. This is the same thing but just visualizing differently. FOIL stands for First Outside Inside Last First multiply the first terms in (a-b)(a-b) a(a)=a^2 Now add the products of the Outside and Inside terms a^2+(a)(-b)+(-b)(a)=a^2-2ab Finally we add.
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View solution steps Quiz Algebra a(a+b)−b(a−b)= Similar Problems from Web Search How do you solve the system 3a − 3b + 4c = −23 , a + 2b − 3c = 25 , and 4a − b + c = 25 ? https://socratic.org/questions/how-do-you-solve-the-system-3a-3b-4c-23-a-2b-3c-25-and-4a-b-c-25
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Formula ( a + b) ( a − b) = a 2 − b 2 It is read as the a plus b times a minus b is equal to the a squared minus b squared. Introduction Let the two literals a and b be two variables. The addition of them form a binomial a + b. The subtraction of them form another binomial a − b. The two binomials are sum and difference basis binomials.
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The basic algebraic properties of real numbers a,b and c are: 1. Closure: a + b and ab are real numbers 2. Commutative: a + b = b + a, ab = ba 3. Associative: (a+b) + c = a + (b+c), (ab)c = a(bc) 4. Distributive: (a+b)c = ac+bc 5. Identity: a+0 = 0+a = a 6. Inverse: a + (-a) = 0, a(1/a) = 1 7. Cancelation: If a+x=a+y, then x=y 8. Zero-factor.
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The ABA and ABAB design are especially useful in applied behavioral analysis (ABA) as they help therapists identify and concentrate on interventions that are successful. Therapists can avoid wasting time with strategies that do little to alter behavior. Related resource: Top 20 Online Applied Behavior Analysis Bachelor's Degree and BCaBA.
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Viewed 220 times. 3. Prove: |a| −|b| | a | − | b | is less than or equal to a − b| a − b |. I sloved this problem by assuming it was right, than checking if a − b > 0 a − b > 0, a a positive\negative b$$ positive\negative than doing the same thing with a − b < 0 a − b < 0. I have a feeling it has a more simple way. absolute-value.
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Algebra Reduce (a-b)/ (b-a) a − b b − a a - b b - a Factor −1 - 1 out of a a. −1(−a)− b b−a - 1 ( - a) - b b - a Factor −1 - 1 out of −b - b. −1(−a)− (b) b−a - 1 ( - a) - ( b) b - a Factor −1 - 1 out of −1(−a)− (b) - 1 ( - a) - ( b). −1(−a+ b) b−a - 1 ( - a + b) b - a Reorder terms. −1(−a+ b) −a+b - 1 ( - a + b) - a + b Cancel the common factor.
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Algebra Simplify (a-b) (a+b) (a − b) (a + b) ( a - b) ( a + b) Expand (a−b)(a+b) ( a - b) ( a + b) using the FOIL Method. Tap for more steps. a⋅a+ab− ba−b⋅b a ⋅ a + a b - b a - b ⋅ b Simplify terms. Tap for more steps. a2 − b2 a 2 - b 2
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In normal regular expression grammar, (a+b)* means zero or more of any sequence that start with a, then have zero or more a, then a b. This discounts things like baa (it doesn't start with a ), abba, and a (there must be one exactly b after each a group), so is not correct. (a*b*)* means zero or more of any sequence that contain zero or more a.
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Otherwise, the result of the binary operation is converted to the type of the left-hand variable, subjected to value set conversion (§5.1.13) to the appropriate standard value set (not an extended-exponent value set), and the result of the conversion is stored into the variable. So your expression does: a^=b^=a^=b; evaluate a.